2006-11-10 10:09:15 · 5 answers · asked by jackal_04 1 in Science & Mathematics ➔ Mathematics
Geometric series: (termFirst - termLastPlusOne)/(1 - ratio):
(e^x -e^(7x))/(1-e^x)
2006-11-10 10:25:26 · answer #1 · answered by sofarsogood 5 · 1⤊ 1⤋
The simplified form of the notation above is called "summation":
x=1
Σ e^(x) (It is read as: "The summation of e^x from x=1 to x=6")
x=6
2006-11-10 18:26:36 · answer #2 · answered by Anonymous · 0⤊ 1⤋
Summation n=1 to n=6 e^(nx)
or
Σ e^(nx) n[1,6
which equals e^(x)+e^(2x)+...e^(6x)
2006-11-10 18:12:41 · answer #3 · answered by bourqueno77 4 · 0⤊ 0⤋
it is most likely e to the power of 6^21
2006-11-10 18:18:29 · answer #4 · answered by Anonymous · 0⤊ 2⤋
Since it is summation the answer is:
e^21
2006-11-10 18:15:22 · answer #5 · answered by venomfx 4 · 0⤊ 2⤋