5(x+1) - (x+1)
would the correct answer be: 4x + 6 ?
if not can you explain the right answer 2 me.. thx :}
2006-11-10 08:19:20 · 10 answers · asked by Britt 1 in Education & Reference ➔ Homework Help
4x + 6 is not quite right
watch the order of operations and distributive properties
repost your answer and I'll tell you if you got it
(you didn't think I'd just give up the answer, did you ?)
2006-11-10 08:24:15 · answer #1 · answered by mike c 5 · 0⤊ 0⤋
The easiest way:
Let: (x+1)=y
therefore:
5(x+1)-(x+1)=
5y-y=
4y
or
4(x+1)=4x+4
Another method:
5(x+1) - (x+1) =
(5x+5) +(-x-1)=
5x+5-x-1= 4x+4 or 4(x+1)
2006-11-10 16:33:18 · answer #2 · answered by j s 2 · 0⤊ 0⤋
5(x+1) = (5x+5)
(x+1) = (1x+1)
5x minus 1x = 4x and 5 minus 1 = 4, so the equation is now 4x + 4
the answer is 4x + 4
2006-11-10 16:29:23 · answer #3 · answered by rosecitylady 5 · 0⤊ 0⤋
no the answer is 4x +4.
5(x+1) - (x+1)
5x+5 - x -1
4x+4 is the answer. distribute the negative to both x and 1 in 2nd step.
2006-11-10 16:23:30 · answer #4 · answered by tahir b 1 · 2⤊ 0⤋
the correct answer is 4x + 4
the (x+1) is being subtracted as a "single unit" if you will...
therefore the - needs to be distributed to the x and the 1
so to get rid of the parentthesees you have to disttibute the negative > -(x+1) becomes -x -1
2006-11-10 16:22:33 · answer #5 · answered by Anonymous · 1⤊ 0⤋
no the correct answer is 4x+4 because when there is a negative sign in front of a grouping symbol ( ) you have to distribute over everything in the parenthsis
2006-11-10 16:22:59 · answer #6 · answered by MoNeYmAkEr 1 · 2⤊ 0⤋
5(x+1)-(x+1)
5x + 5 - x -1
4x+4 is the answer
The answer would be 4x+6 if the equation was
5(x+1)-(x-1)
5x + 5 - x +1
4x +6
Hope this helps
2006-11-10 16:22:56 · answer #7 · answered by alanjb 1 · 1⤊ 1⤋
5(x+1)-(x+1)
=5x+5-x-1
=5x-4x+5-1
=4x+4
2006-11-10 17:54:32 · answer #8 · answered by alpha 7 · 0⤊ 0⤋
no, it's wrong
it's: 4x+4
5(x+1) - (x+1)
distribute: 5x + 5 - x -1
combine like terms: 5x - x and 5 - 1
so the answer is 4x + 4
2006-11-10 16:24:05 · answer #9 · answered by Gigi 2 · 1⤊ 2⤋
Umm... I would do it by going on math.com
2006-11-10 17:25:40 · answer #10 · answered by Anonymous · 0⤊ 1⤋