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Graphing linear equation with 3 variables?
Ok I'm stumped on how to graph this.
Here is the problem.
120s+150m174L=36000
30s+36m+48L=9000
4s+4m+4L=1000
I have solved for the variables and gotten
s=125
m=83.333
L=41.666
Any idea of how I would go about graphing this?
The s,m,and L are all quantities of cots sold and the the final is the number of parts available. 36000 is tubing, 9000 is canvas, and 1000 is connectors.
Thanks for any help,
Scott

2006-11-10 06:50:13 · 3 answers · asked by swierzycki 2 in Science & Mathematics Mathematics

3 answers

Well, you see, you need to subsitute 2 variables to get the third one. So use 1, S=1, M=1, and then you find L. With that, just plot 3 points, then make S=2, M=2, then find L, plot the graph and so on and so on.

2006-11-10 06:53:53 · answer #1 · answered by Webballs 6 · 0 0

% 3 distinctive values for x and replace x in the equation one-at-a-time. each and every time clean up the ensuing equation for y. This types a "element" on the graph.. when you consider which you used a similar linear function, the three factors would be co-linear (i.e., all on a similar at present day line.)

2016-10-21 14:49:36 · answer #2 · answered by mcsweeney 4 · 0 0

Your solution is a point in 3 dimensional space. You can fix a coordinate at its value and plot the other two:

Set s = 125, now your equations are straight lines in the m-l space,

Do the same for the other coordinates. You'll get 3 plots.

There are 3 dim plotting programs but....I'm not sure how useful they'd be.

2006-11-10 07:38:05 · answer #3 · answered by modulo_function 7 · 0 0

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