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500
50.2
5.21
+ 0.221
___________

I need to know how many significant figures in the answer. I know when you add it up it comes to 555.631 but I think I have to round it because of the figure 500 has no decimals. Help!

2006-11-10 04:40:15 · 5 answers · asked by Anonymous in Science & Mathematics Chemistry

5 answers

I would think that since no summand has more than 3 significant digits, that you should round your answer to 3 significant digits, namely:

556

Another rule is that you should round your answer to have the same number of places after the decimal as the one with the fewest decimals. Again, 500 has no decimals, so you should round to a whole number:

556

2006-11-10 04:43:53 · answer #1 · answered by Puzzling 7 · 0 0

When you are adding numbers, you want to look at the number of decimal places.when
I add numbers, the result is only accurate to the smallest number of decimal places I am adding. In this case, since 500 has no decimal place, that is all I can keep in ur sum.so the result becomes 556 with no decimal points

2006-11-10 04:52:08 · answer #2 · answered by Anonymous · 0 0

With addition, you go to the one with the least decimal places. That means, NO decimal places...like you said...


555.631 becomes 556

2006-11-10 04:44:11 · answer #3 · answered by Anonymous · 0 0

rules for addition are distinctive than rules for multiplication first, get all exponents equivalent: 40 3.5E2 + 2671.1E2 + 8.09E2 then upload: 2722.69E2 rounded to least form of digits good of decimal (a million): 2722.7E2 then ultimately: 2.7227E5 observe, you will possibly have long previous: 0.435E4 + 26.711E4 + 0.0809E4 27.2269E4 rounded to least form of digits good of decimal (3): 27.227E4 with comparable result: 2.7227E5

2016-10-21 14:37:43 · answer #4 · answered by Anonymous · 0 0

in your answer you should have 3 sig.figs as all your added number consist of 3 sig.figs ,, so the correct significant answer will be 556 and your uncertainity will be (+,- 1)

2006-11-10 04:53:13 · answer #5 · answered by source_of_love_69 3 · 0 0

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