opening night of the latest summer blockbuster sold out the local theater 550 seats. if regular ticket price is 7 dollars and seior ticket price is 5 dollars how many regular tickets and how many senior tickets were sold if the total amount collected was 3480
2006-11-10 03:25:26 · 11 answers · asked by Rexignis 1 in Science & Mathematics ➔ Mathematics
No of senior tickets sold=185 and No of regular tickets sold=365. I would show u how to resolve the system of equations but i'm not sure it's the proper or simplest way to do that (next time specify what grade ure in so we'll konw)
2006-11-10 03:33:51 · answer #1 · answered by red 3 · 0⤊ 0⤋
Let
x = senior
Y = Regular
5x = cost of senior Tickets
7x = cost of regular Tickets
550 = Total seats
3480 = Total cost Collected
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x + y = 550 - - - - - - -Equation 1
5x + 7y = 3480- - - - - Equation 2
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Substitute Method Equation 1
x + y = 550
x + y - x = 550 - x
y = 550 - x
The answer is y = 550 - x
Insert the y value into equation 2
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5x + 7y = 3480
5x + 7(550 - x) = 3480
5x + 3850 - 7x = 3480
-2x + 3850 = 3480
-2x + 3850 - 3850 = 3480 - 3850
- 2x = - 370
- 2x/-2 = - 370/ -2
x = 185 . . .Seniors
The answer is x = 185
Insert the x value into equation 1
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x + y = 550
185 + y = 550
185 + y - 185 = 550 - 185
y = 365. . . .Regular
The answer is y = 365
Insert the y value into equation 1
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Check for equation 1
X + y = 550
185 + 365 = 550
550 = 550
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Check for equation 2
5x + 7y = 3480
5(185) + 7(365) = 3480
925 + 2555= 3480
3480 = 3480
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There were 185 senior tickets = $ 925.00
There were 365 Regular Tickets = $ 2555.00
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The solution set is { 185, 365 }
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2006-11-10 07:12:21 · answer #2 · answered by SAMUEL D 7 · 0⤊ 0⤋
u can use a table..
so if 100 seat is $7 and 450 seat is $5 = $700 + $2250 = $2950
so 110 seat of $7 and 440 seat of $5 = $770 + $2200 = $2970
so 300 seat of $7 and 250 seat of $5 = $2100 + $1250 = $3350
so 350 ($7) and 200 ($5) = $2450 + $1000 = $3450
so 365 ($7) and 185 ($5) = $2555 + $925 = $3480
2006-11-10 03:34:19 · answer #3 · answered by kohjustin1988 1 · 0⤊ 0⤋
3480 = 7x + 5y
550 = x + y
x = 550 - y
3480 = 7(y - 550) + 5y
3480 = 7y - 550 +5y
3480 = 12y -550
4030 = 12y
335.833 = y
x = 550 - 335.833
x = 214.1666
Answer : senior tickets sold = 336
regular tickets sold = 214
2006-11-10 04:55:49 · answer #4 · answered by missy 4 · 0⤊ 0⤋
lets see, if x is regular tickets and y is senior tickets:
7x + 5y = 3480
and
x + y = 550
so x = 550 - y
replace x in the first equation
7(550 - y) + 5y = 3480
solve for y, then you can get x based on that.
2006-11-10 03:28:42 · answer #5 · answered by Kutekymmee 6 · 0⤊ 0⤋
Regular tickets sold: 321
Senior tickets sold: 229
Ratio method.
2006-11-10 06:05:14 · answer #6 · answered by Anonymous · 0⤊ 0⤋
x: regular seat
y:senior seat
x+y=550
7x+5y=3480
x=550-y
7(550-y) + 5y = 3480
3850 - 7y + 5y = 3480 => 2y = 370 => y= 185
x = 365
2006-11-10 04:26:37 · answer #7 · answered by Anonymous · 0⤊ 0⤋
r=regular
s=senior
r=s=550
7r+5s=3480
r=550-s
7(550-s)+5s=3480
3850-7s+52=3480
-2s=-370
s=185
r=550-185=365
365 regular tickets
185 senior tickets
check
365*7+185*5=2555+925=3480
2006-11-10 03:32:32 · answer #8 · answered by yupchagee 7 · 0⤊ 0⤋
let x regular tickets so 550-x senior
so 7x+ 5(550-X) = 3480
so 2750 + 2x = 3480
or 2x = 730
x= 365 regular tickets
2006-11-10 03:30:09 · answer #9 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
no clue
2006-11-10 03:39:47 · answer #10 · answered by Cheer 4 Fun 1 · 0⤊ 1⤋