x=0.66666666666.........................................
10x=6.666666666.........................................
subtracting 1 from 2
9x=6
x=6/9=>2/3
2.0.35
=35/100
7/20
3.0.37506
=37506/100000
=18753/50000
2006-11-10 02:32:28
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answer #1
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answered by raj 7
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Repeating decimal, there's a very nice trick.
For example the repeating decimal is 0.6666. The repeating element here is 6. Then the fraction is 6/9.
Or another example, 0.2323232323... = 23/99. 0.200620062006... = 2006/9999. Check it out.
The rule for this is, the numerator is the repeating element and the denominator is a number that consists of only 9's. The number of 9's equals to the length of the repeating element.
2006-11-10 10:44:12
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answer #2
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answered by PSV 2
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Decimal is a representation of tenths, hundredths, so any decimal begins over some power of 10
e.g. 35/100. You then simplify the fraction to 7/20 (simplified by 5 in this case).
.6 is read as six-tenths, so it starts out as 6/10. Simplified by 2, it becomes 3/5.
.375 starts as 375/1000. I'll let you simplify it.
I can't help with the repeating decimal example.
2006-11-10 10:32:48
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answer #3
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answered by MrCabal 2
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the decimal is say (0.66666)/(1.0) which basically is a fraction, then you have to multiply the top and bottom of the fraction by integers untill the top is an integer So
(0.6666)/(1.0) * (6.0)/(6.0) = (3.9999)/(6.0) which is approxamatly
4/6 or 2/3 which is the correct answer.
multiplying the top and the bottom by the same number say 6/6 is ok to do and doesn't break any "rules"
2006-11-10 10:35:09
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answer #4
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answered by tranquilllity 2
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single digit repeating .. divide by 9.
ie 0.66666666.... is 6/9 = 2/3
or 0.33333333333333 is 3/9 or 1/3
two digits repeating divide by 99
ie 0.353535.... is 35/99
2006-11-10 10:36:27
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answer #5
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answered by sri 1
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x = 0.1234567891...
10^9 x = 123456789.1234567891... = 123456789 + x
10^9 x - x = 123456789
(10 ^ 9 -1 ) x = 123456789
x = 123456789 / (10 ^ 9 - 1)
2006-11-10 10:45:30
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answer #6
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answered by gjmb1960 7
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buy a calculator!!
2006-11-10 10:35:27
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answer #7
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answered by Anonymous
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