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Can anyone please tell me why long wires provie more resistance than short wires in as much scientific detail as possible? Ignoring thickness. I'm confused... is it because more electrons collide with more atoms, increasing the energy transfer form kinetic energy to thermal energy? S.O.S

2006-11-10 02:01:26 · 8 answers · asked by ? 1 in Science & Mathematics Physics

8 answers

The following is from Wikipedia:

"In a normal conductor, an electrical current may be visualized as a fluid of electrons moving across a heavy ionic lattice. The electrons are constantly colliding with the ions in the lattice, and during each collision some of the energy carried by the current is absorbed by the lattice and converted into heat (which is essentially the vibrational kinetic energy of the lattice ions.) As a result, the energy carried by the current is constantly being dissipated. This is the phenomenon of electrical resistance."
(See "superconductor")

As to length and disregarding superconductors, any unit length n of a material has the property of electrical resistance. Since resistances in series add, a length 2n will have 2 times the resistance of a length n, etc. Also see "resistance" in wikipedia, where rho is defined.

2006-11-10 02:39:42 · answer #1 · answered by Gary H 6 · 0 0

since resistance depends upon

R= (l*ρ)/A

where l is the length of the conductor.
A is the cross-sectional area, measured in square meters
ρ (Greek: rho) is the electrical resistivity (also called specific electrical resistance) of the material, measured in ohm · meter. Resistivity is a measure of the material's ability to oppose the flow of electric current

A metal consists of a lattice of atoms, each with a shell of electrons. This can also be known as positive ionic lattice. The outer electrons are free to dissociate from their parent atoms and travel through the lattice, creating a 'sea' of electrons, making the metal a conductor. When an electrical potential difference (a voltage) is applied across the metal, the electrons drift from one end of the conductor to the other under the influence of the electric field.

In a metal the thermal motion of ions is the primary source of scattering of electrons (due to destructive interference of free electron wave on non-correlating potentials of ions) - thus the prime cause of metal resistance. Imperfections of lattice also contribute into resistance, although their contribution in pure metals is negligible.

The larger the cross-sectional area of the conductor, the more electrons are available to carry the current, so the lower the resistance. The longer the conductor, the more scattering events occur in each electron's path through the material, so the higher the resistance.

2006-11-10 02:09:03 · answer #2 · answered by Mysterious 3 · 1 1

Paralleling small wires to develop their modern carrying potential is easily opposite to the national electric Code. Use an even bigger cord extremely. That answer is likewise probable to be greater fee-effective. The 12 gauge could be waiting to deal with the present except that is bundled with countless different wires. even with the undeniable fact that, voltage drop may well be a difficulty, so which you're able to might desire to circulate with an even bigger cord than may well be mandatory to maintain IR voltage drop below administration. If the run is rather long, that is beneficial to evaluate working at a greater robust voltage on the line end stepping the voltage down on the burden end with a transformer to decrease the effects of IR voltage drop. there's a good reason that the voltage is stepped up for transmission over long distances.

2016-11-23 14:08:29 · answer #3 · answered by Anonymous · 0 0

No you are wrong. there is this formula to calculate the resistance of the wire

R= pl/A

as u can see

p: resistivity that is dependent on the material ['p' is the greek letter rho]

so its a constant.

A is the area of cross-section, that too is constant.

so, R is directly proportional to l

which means greater the length, greater the resistance.

2006-11-10 02:10:46 · answer #4 · answered by Srikanth 2 · 0 0

Imagine a pressurized water tank. Connect a narrow hose to it and open the valve. You'll get a certain flow of water because the hose is a certain size and length. If you make the hose twice as long, the flow of water decreases by exactly two times. If we imagine the hose to have "friction", then by doubling its length, we double its friction. The same with electricity and wires. Double the length of the wire, and you double the friction.
THE FRICTION IS THE "OHMS, IT IS THE ELECTRICAL RESISTANCE.

2006-11-10 02:15:25 · answer #5 · answered by silty1234 1 · 0 1

you are basically correct in your assumption. There is more "stuff" to get in the electrons way so therefore more resistance. no point getting too technical here if you just want a lyamans answer, right?

2006-11-10 02:13:46 · answer #6 · answered by Stuart T 3 · 0 0

the weight that the short wire takes x length of the wire..a longer wire has more resistance ....just a guess.

2006-11-10 02:07:07 · answer #7 · answered by Ken and Wendy M 6 · 0 0

their really really mean!!

2006-11-10 02:02:47 · answer #8 · answered by Anonymous · 0 1

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