What is the Lewis Structure for NCS(minus) and how do you determine it?

Question

Please help me out, this is a problem I've been working on all morning and still nothing.

Answer 1

[N=C=S]- with 2 pair of electrons for each: N & S. Count the valence electrons for each atom (5 for N, 4 for C & 6 for C) plus an electron for the minus. You have a total of 16 electrons. Draw the structure. Every bond contains 2 electrons, so inicialy you'll see that you only have 4, put the other as pair of electrons around each atom (respecting the octect rule- 8 electrons for each atom-except for H that only can have 2- and families after period 2 don't necessarly respect it, but for now you can ignore this last fact). After you do this you'll see that you have more electrons than needed, this is where you have draw double or triple bonds. Count the bonds and pair of electrons (each have 2) until you are sure you have your 16. [ ] are to indicate charge.