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The owner wants 5 foot wide decks along either side and 10 foot wide decks at the two ends. Find the dimensions of the smallest piece of property on which the pool can be built satisfying these conditions.

2006-11-10 01:18:51 · 5 answers · asked by ben_ev0lent 1 in Science & Mathematics Mathematics

5 answers

You can have different sizes of the pool, for example:
20 ft. wide pool 1800:20=90ft. long
or 25ft. wide pool 1800:25=72 ft. long
or 30 ft. wide pool 1800: 30=60 ft. long
I would clarify with the owner what pool width he or she prefers.
For the side decks we add 2x5 ft.=10ft to the chosen width of the pool
For the end decks we add 2x10ft.=20 ft.to the length of the pool

thus the pool site should be over

(20 +10) x (90+10)=30'x100'
or
(25+10) x (72 + 10)=35' x 82'
or
(30 + 10)x (60+10)= 40'x 70'

Please remember to add the pool clearances from the property line as per local municipal codes. Also, the machines used for digging have to have access from this property, not from the neighbours yards. The smaller they are the more difficult and expensive the job is.
If we add about 10 ft. for access (and clearance) on each side we end up with a poll site:
(20+20)x(90+20)=40'x110'
(25+20)x(72+20)=45'x92'
(30+20) x(60+20)=50'x80'

An addition of the area needed for the house will give you the minimum lot size required.
Good luck!

2006-11-10 02:34:36 · answer #1 · answered by Anonymous · 0 0

The least amount of space taken up by the deck would be when the length is twice the width. That would give dimensions of the pool 30X60ft.......1800 sq ft...and the area for the deck of a pool with those dimensions would be 1400 sq ft. So the smallest piece of property would have to be 3200 sq ft for this pool and deck, or 40x80 ft.

2006-11-10 01:46:24 · answer #2 · answered by carrieinmich 3 · 0 0

If the swimming pool is to be built with an area of 1800 square feet,
the following length and breadth are possible
1x1800, 2x900 and so on.
the least dimension would be 30x60 with additonal deck of 10 and 20 ft respectively. therefore smallest property required is (30+10)x(60+20)=3200 sqft.

2006-11-10 02:08:03 · answer #3 · answered by Anonymous · 0 0

For any quadrilateral, the minimal area is always a square. So, for this problem, based on the area of the pool and the fact that it must be rectangular, the closest to square would be a pool of 45' x 40'. Adding in the dimensions of the deck, you get a the total dimensions of 65' x 50', or a total area of 3,250 sqft.

2016-05-22 02:33:49 · answer #4 · answered by Anonymous · 0 0

take lenth 60feet nad wideth as 30feet.u can get 1800sqfeet.for teh decks subtract 20 from 60 and 10 from 30 remaning 40 nad 20 will be teh lenth and breath of swimmimg pool. 1200 sq feet willbe swimming pool

2006-11-10 01:31:33 · answer #5 · answered by cipotli 4 · 0 0

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