find me the ans for 2x^+12x+18=?

Answer 1

You mean find solutions for x when 2x^2+12x+18=0.

First we can divide thru by 2 just to make it simpler.
x^2+6x+9=0 , then factor and get
(x+3)^2=0
so x=3.

Answer 2

6x - 3y = 21 2x + 2y = 22 6x - 3y = 21 -3y = 21 - 6x y = 21/-3 - 6x/-3 y = -7 + 2x y = 2x - 7 2x + 2y = 22 2x + 2(2x - 7) = 22 2x + 4x - 14 = 22 6x - 14 = 22 6x = 36 x = 6 6x - 3y = 21 6(6) - 3y = 21 36 = 3y + 21 36 - 21 = 3y 15 = 3y 5 = y y = 5 verify x = 6 y = 5 6x - 3y = 21 6(6) - 3(5) = 21 36 - 15 = 21 21 = 21 The identity shows that the values x = 6 and y = 5 are the superb option for the above equation. 2x + 2y = 22 2(6) + 2(5) = 22 12 + 10 = 22 22 = 22 The identity shows that the values x = 6 and y = 5 are the superb option for the above equation.

Answer 3

2x^2 + 12x + 18 = 0

2(x^2 + 6x + 9) = 0

2(x + 3)(x + 3) = 0

x + 3 = 0 x + 3 = 0

x = -3 x = -3

the solution is {-3}

to check your solution, substitute -3 back into your original equation:

2(-3)^2 + 12(-3) + 18 = 0

2(9) + (-36) +18 = 0

18 + (-36) +18 = 0

0 = 0

Answer 4

Earlier answer of -3 is correct if problem is truly 2x^2+12x+18=0.

2 (x^2+6x+18) =0

2 (x+3) (x+3) = 0

2=0 (x+3)=0 (x+3) = 0

unknown x=-3 x=-3

Answer 5

2x^2+12x+18
=2(X^2+6x+9)
= 2 (x+3)^2

Answer 6

first factor out the common factor 2

2 ( x ^ 2 + 6x + 9 )

then, notice that the first term inside is x^2 so just think of

two numbers that when you add the middle term 6 will result and when you multiply the answer will be 9
and that is 3 and three

it goes this way (x + 3 ) ( x + 3 )


and go to the question , it will become 2 ( x+3 ) ( x+3 )

Answer 7

to solve for the value of x,

2x^2 + 12x + 18 = 0
(2x + 6) (x + 3) = 0

for (2x + 6) = 0,
x = -3

similarly, for (x + 3) = 0,
x = -3

Answer 8

x = -3

Answer 9

x=-3

Answer 10

Assuming you mean

2*x^2 +12*x+18=0

2*(x^2+6*x+9)=0
2*(x+3)(x+3)=0
x=-3 double root