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if so email me cottonsugar987654321@yahoo.ca

2006-11-09 23:51:10 · 7 answers · asked by ~Hanan~ 1 in Science & Mathematics Mathematics

7 answers

Example:
4^x = 8

The technique here is we change both sides into the same base. Since we know that 4 = 2² and 8 = 2³, then we can change the equation into
2^2x = 2^3

Then, since the bases are equal, then the exponents must also be equal. Thus,
2x = 3

Therefore,
x = 3/2.

----------------------------
The thing here is to change both sides into the same base.
Another example:
81^[x(x + 2)] = 1/3^(9 - 20x)

We change both bases: 81 = 3^4, 1/3 = 3^-1. Thus,
3^[4x(x + 2)] = 3^[-(9 - 20x)]

We then equate the exponents:
4x(x + 2) = (20x - 9)

We distribute:
4x² + 8x = 20x - 9

We transpose everything to the left
4x² - 12x + 9 = 0

We factor out
(2x - 3)² = 0

Square root both sides
2x - 3 = 0

We transpose -3
2x = 3

Divide 2. Therefore,
x = 3/2

--------------------------
Here's another example:

2^x = 3

I know that it is VERY DIFFICULT to change 3 into a power of 2. Here, we use another tool: the logarithm. If you are already ready, you can inform me so that I can teach you that. Please feel free to contact me.

kevin!
^_^

2006-11-10 00:12:29 · answer #1 · answered by kevin! 5 · 0 0

it is depend in how it is expressed.
one example is

2 ^ x = 64

just take the base of the term with exponent x and take it as your new base. then, try to multiply it by itself ( repeatedly if needed ) until you get the answer of 64, and that is 6

next, count how many times you have used your base x

it will look this way: 2 ^ x = 2 ^ 6

so the answer is x= 6

it is true to any variable.

2006-11-10 08:09:29 · answer #2 · answered by jdash01 3 · 0 0

Yea it is very easy just on question are you learning in college?? School? Where may you be learing this? Because if you telll me what grade you are in i will find a way to help you!

2006-11-10 08:14:01 · answer #3 · answered by Moe 2 · 0 0

well best way to solve these is to apply numerical analysis. Search the web u will find some examples.

2006-11-10 08:12:23 · answer #4 · answered by lalalala 2 · 0 0

me... i know how to solve exponential equations.....

just use logarithm in solving exponential functions or equations..

2006-11-10 08:02:10 · answer #5 · answered by ryan i 1 · 0 0

Give me some examples. You can mail me at my
Answers ID - albert.

2006-11-10 08:09:04 · answer #6 · answered by albert 5 · 0 0

yea, here is an example

y=e^x solve for x
Ln(y) = Ln(e^x)
Ln(y)= x*Ln(e) , Ln(e) =1
x= Ln(y) , so were done

2006-11-10 08:08:10 · answer #7 · answered by dragongml 3 · 0 0

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