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2006-11-09 21:47:46 · 7 answers · asked by supremecritic 4 in Science & Mathematics Physics

7 answers

its impulse change in momentum

2006-11-09 22:04:55 · answer #1 · answered by gracious_78 3 · 0 0

There are several terms for the rate of change, impulse being one of them.

Graphically, an impulse change looks like a thin (small time step) square wave. When you hit a pool ball with a cue stick, you impart an impulse of momentum.

A longer (to infinite time) square wave is considered a "constant" rate of change.

Other types:
Ramp, or saw-tooth
Exponential
Sinusoid
many others...

2006-11-10 05:54:44 · answer #2 · answered by cfpops 5 · 0 0

Impulse is change in momentum.Force=change in montum / time.So change in momentum = Force x time = impulse.

2006-11-10 05:53:33 · answer #3 · answered by Anonymous · 0 0

You can easily prove that
Impulse=Force*Time (1)
Force=mass*acceleration (2)
and
acceleration=rate of change of velocity with time(3)
combining (2) and (3) we get
Impulse is rate of change of momentum

2006-11-10 07:33:10 · answer #4 · answered by Napster 2 · 0 0

F = ma = d(mv)/dt (the more general form)
Impulse = ∫Fdt = ∫d(mv)
Impulse, therefore is change in momentum

2006-11-10 06:01:42 · answer #5 · answered by Helmut 7 · 0 0

impulse = F * dt NOT dF / dt

nai F*dt = m*a*dt = m * du/dt * dt (dt canclels out)
so impulse = m*du/dt

therefore the final product is actually momentum

not rate of change of momentum

chang in momentum strictly.

2006-11-10 06:18:59 · answer #6 · answered by Emmanuel P 3 · 0 0

impulse is change iin momentum

f*t=m*v

2006-11-10 08:25:48 · answer #7 · answered by Anonymous · 0 0

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