Mother's genotype is X*X and dad's genotype is XY.
X*X -------> 1/2 X* & 1/2 X
XY --------> 1/2 X & 1/2 Y
Kids genotype will be: 1/4X*X, 1/4XX, 1/4X*Y, 1/4XY
Therefore, there is a 25% chance of having a daughter who is a carrier, 25% chance of having a daughter who is not a carrier, 25% chance of having a hemophilic son and 25% chance of having a healthy son.
2006-11-09 16:18:29
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answer #1
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answered by smarties 6
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Hmm ... you didn't complete the question. "... that a child would ..." what? Have the trait? Or be a carrier? The chances are 50% that the child would have (exhibit) the trait. The chances are 75% that the child would be a carrier. The above is assuming that it is a typical X-linked recessive trait (which is the majority of cases of sex-linked traits). We can assume this because the question says that the woman is a carrier, but does not say she is an exhibitor of the trait. (I.e. if it were a X-linked dominant trait, and being a carrier would make the mother exhibit the trait, then the question would say so.) If it were an X-linked dominant trait, then not only would she exhibit the trait herself, but the odds of the child *exhibiting* the trait would go up ... perhaps as high as 75% ... as the mother would be passing the trait on to all daughters and half her sons. Oh, and we know it's not a Y-linked trait because it says the mother is a carrier.
2016-05-22 02:00:09
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answer #2
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answered by Anonymous
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The mother is X*X and the father is XY which means that the four possibilities are X*X X*Y XX XY. That means 25% carrier female, 25% afflicted male, 25% healthy female, and 25% healthy male.
2006-11-09 15:51:18
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answer #3
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answered by kihela 3
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The chance of having afflicted children is none as only
HH and Hh genotypes can be produced. But the chance of
having a carrier child is 50%. The chance of having either a son
or daughter is also 50% unless the man has some special condition.
2006-11-09 15:53:51
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answer #4
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answered by burnt_splint 1
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25% chance of a carrier
25% chance of afflicted son
0% chance of an afflicted daughter
(You use a punnet square.)
Because the trait is sex-linked, if a male has one allele for the trait he will have the trait.
2006-11-09 15:55:02
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answer #5
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answered by moonfreak♦ 5
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I would check that with a doctor. That is VERY serious stuff. The Russian Czars family had that problem and therefor it has been called the royal disease or the disease of kings.
2006-11-09 15:51:03
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answer #6
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answered by Anonymous
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50% of your kids will be carriers.
so if you had 2 girls and 2 boys..1 boy might carry it and one girl might carry it.
being a carrier doesn't necessarily mean they will have it. it juss means that they can pass it on to their children.
2006-11-09 15:52:23
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answer #7
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answered by babyboo 1
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