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how do i rearange "a=(v-c)/t" to solve for "c"

2006-11-09 15:43:40 · 9 answers · asked by dmsous 2 in Science & Mathematics Mathematics

9 answers

Hello, I would be glad to help you with this:

a=(v-c)/t
at=v-c
-c=at-v
c=v-at

I hope this helps and good luck with the rest of your course work ,Please Please remember me for best answer

2006-11-09 15:51:37 · answer #1 · answered by Jaym 2 · 0 0

that is one of the things that a person must know about algebra

First, you are finding for c and it is inside the parenthesis with

a fraction, you must first simplify the fraction by multiplying both sides by variable t like this:

at = v - c

then transpose the variable v to the left because you are

looking for c

like this at - v = -c

the sign of the variable v will be negative if you transpose it .

then finally, divide both sides by negative 1 to make the variable

c be positive.

it will be -at +v =c arranging it to make the first term positive

the answer is v - at = c

hope you understand!

2006-11-12 08:35:25 · answer #2 · answered by jdash01 3 · 0 0

a=v-c/t
multipy oth sides by t
at=v-c
add c-at to both sides
then
c=v-at

2006-11-10 07:42:05 · answer #3 · answered by grandpa 4 · 0 0

multiplying by t
at=v-c
adding -v
at-v=-c
multiplying by-1
v-at=c

2006-11-09 23:57:12 · answer #4 · answered by raj 7 · 0 0

a=(v-c)/t

at=v-c

at-v=-c

-at+v=c

also written as v-at=c

2006-11-10 00:34:39 · answer #5 · answered by Raina 2 · 0 0

http://www.hostsrv.com/webmab/app1/MSP/quickmath/02/pageGenerate?site=quickmath&s1=equations&s2=solve&s3=basic

2006-11-09 23:45:51 · answer #6 · answered by hillbilly_coon 3 · 0 0

a = (v-c) / t
at = v - c
c = v - at

2006-11-09 23:45:22 · answer #7 · answered by novangelis 7 · 0 0

a=(v-c)/t
at=v-c
-c=at-v
c=v-at

2006-11-09 23:48:10 · answer #8 · answered by yupchagee 7 · 0 0

a*t=v-c
(a*t)-v=-c
v-(a*t)=c

2006-11-09 23:51:57 · answer #9 · answered by Mariposa 7 · 0 0

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