Solve the equation for x.
(x - 5)^2 = 27
can you show me the steps I'm confused
2006-11-09 15:40:07 · 14 answers · asked by jazminda S 1 in Science & Mathematics ➔ Mathematics
5+-V92
quadratic formula
2006-11-09 15:49:41 · answer #1 · answered by Jaym 2 · 0⤊ 0⤋
This 1 is simple because someone already completed the square for you
(x - 5)^2 = 27 take sqrt of both sides
x-5=+/-3*sqrt(3)
x=5+/-3*sqrt(3)
2006-11-09 23:52:07 · answer #2 · answered by yupchagee 7 · 0⤊ 0⤋
You can take the square root of both sides and you find out that the square root of 27 is equal to x-5. Then, you add 5 and get that the square root of 27 plus 5 equals x. Which is about equal to 10.196152. Then, you can plug it in for x to see if you are right.
(10.196152-5)=5.196152
(5.196152)^2=27
So, it is right! But remember that the above numbers are decimal approximations.
2006-11-09 23:46:29 · answer #3 · answered by sg 3 · 0⤊ 0⤋
8 where y = 4. How did I do?
2006-11-09 23:58:24 · answer #4 · answered by sweetirsh 5 · 0⤊ 0⤋
(x - 5)^2 = 27
x - 5 = ± â27 = ± 3â3
x = 5 + 3â3,5 - 3â3
2006-11-09 23:49:48 · answer #5 · answered by Helmut 7 · 0⤊ 0⤋
(x-5)^2 = 27
x^2 - 10x +25 = 27
X^2 - 10x -2 = 0
use the quadriatic formula to solve for x
2006-11-09 23:42:32 · answer #6 · answered by scurvybc 3 · 0⤊ 0⤋
(x - 5)^2 = 27
x - 5 = sqrt(27)
x = 5 ± sqrt(9 * 3)
x = 5 ± 3sqrt(3)
2006-11-10 00:01:14 · answer #7 · answered by Sherman81 6 · 0⤊ 0⤋
I would think that if (x - 5)^2 = 27. then
x - 5 = sq.rt. 27 = 5.196
Therefore, x = 5.196 + 5
x = 10.196
2006-11-09 23:49:47 · answer #8 · answered by Richard S 6 · 0⤊ 0⤋
take the square root of each side.
so then it would x - 5= square rook of 27
so then if you subtract 5 onto the other side
x = 5(+ -) 7
so x could be 12 or -2
2006-11-09 23:49:11 · answer #9 · answered by neonpony1919 3 · 0⤊ 0⤋
(x-5)^2 = 27 =(3*sqrt(3))^2
take square root on both sides
(x-5) = +/- 3*sqrt(3)
so x = 5 + 3sqrt(3) or 5-3sqrt(3)
2006-11-09 23:48:54 · answer #10 · answered by Mein Hoon Na 7 · 0⤊ 0⤋