how do i rerange "d=vt+1/2at[2]"to solve for "a"
2006-11-09 15:00:33 · 6 answers · asked by dmsous 2 in Science & Mathematics ➔ Mathematics
Great "How fast is the car moving" formula.
d = vt + 1/2 at^2
1/2 at^2 = d - vt
at^2 = 2d-2vt
a= (2d - 2vt) / t^2
2006-11-09 15:12:04 · answer #1 · answered by Richard S 6 · 0⤊ 0⤋
d = vt + 1/2at(2)
The 1/2 and 2 divide out-- leaving
d = vt + at
To solve for a divide by t--
d - vt = at
a = (d-vt) / t
2006-11-09 23:14:38 · answer #2 · answered by j 4 · 0⤊ 0⤋
subtracting vt
d-vt=vt+1/2a(t)^-vt
d-vt=1/2at^2
multiplying by 2
2(d-vt)=at^2
dividing by t^2
2(d-vt)/t^2=a
2006-11-09 23:04:43 · answer #3 · answered by raj 7 · 0⤊ 0⤋
d-vt=1/2at^2
2(d-vt)=at^2
(2(d-vt))/t^2=a
2006-11-09 23:05:49 · answer #4 · answered by silent rain 2 · 0⤊ 0⤋
a=(vt+1/2t[2]-d)/a
2006-11-09 23:02:44 · answer #5 · answered by ette-chan ♥ 2 · 0⤊ 1⤋
d=vt+at
d=t(v+a)
d/t=v+a
d/t-v=a
2006-11-09 23:05:37 · answer #6 · answered by L 4 · 0⤊ 0⤋