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2006-11-09 14:26:16 · 24 answers · asked by cowgirl_up1228 1 in Science & Mathematics Mathematics

24 answers

2(3-10x)+4 (5x+2)=-6

6-20x+20x+8=-6

14=-6 Impossible

2006-11-09 14:34:55 · answer #1 · answered by futureastronaut1 3 · 2 0

2(3-10x)+4 (5x+2)=-6

6-20x+20x+8=-6

14= -6

This is not possible. Thus, the equation above does not have any solution. There is value of x that can satisfy the equation.

2006-11-09 22:40:27 · answer #2 · answered by Sindhoor 2 · 1 0

2(3-10x)+4 (5x+2)=-6 both side divided by 2
(3-10x)+2 (5x+2)=-3
3-10x+10x+4=-3
3- 4 = -3 wrong question

2006-11-09 22:48:46 · answer #3 · answered by safrodin 3 · 0 0

2(3-10x)+4(5x+2)= -6

6-20x + 20x+8=-6

6+8 = -6

14 does not equal -6

2006-11-09 22:37:36 · answer #4 · answered by llarsen78 1 · 1 0

2(3-10x)+4(5x+2)=-6
multiply through with the two and the four - 6-20x+20x+8=-6
combine like terms - 14+40x=-6
isolate the variable - 40x=-20
solve for x - x=-1/2

2006-11-09 22:29:43 · answer #5 · answered by NeRdYkId1101 3 · 0 1

10

2006-11-09 22:44:37 · answer #6 · answered by Erin M 1 · 0 1

x=20

2006-11-09 23:09:43 · answer #7 · answered by J 6 · 0 1

square
36 = 4(3-10x)^2 + 16(5x+2)^2 +16(3-10x)(5x+2)
4(100x^2 -60x + 9) => 400x^2 -240x +36
16(25x^2 -20x + 4) => 400x^2 -320x +64
16(-50x^2 -5x + 6) => -800x^2 - 80x + 96

36 = -640x + 196
36 - 196 = -640x
x = 1/4

2006-11-09 23:07:03 · answer #8 · answered by The Clueless Philospher 2 · 0 1

2(3-10x)+4 (5x+2)=-6
6-20x+20x+8=-6
-20x+20x=-6-6-8
0=-20

there is no solution to this problem.

2006-11-10 00:18:33 · answer #9 · answered by yupchagee 7 · 0 0

no seriously 14

6-20x+20x+8 got 2 look at the sign in front of the #, -20x+20x cancels out = 0

6+8=14 14+0=14

2006-11-09 22:31:01 · answer #10 · answered by 约瑟夫 3 · 0 1

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