Two Train are moving in opposite direction @ of 50km per hour and 90 km per hour, their length are 1.10kmand 0

Question

Two Train are moving in opposite direction @ of 50km per hour and 90 km per hour, their length are 1.10kmand 0.9km. The time taken by the slower train to cross the fast train in second is?

Answer 1

the one who answered first... plzzzzzzzzzz

excellent answer but.. trains moving towards each other can also be said to move in opp directions.

Answer 2

Two Train are moving in opposite direction @ of 50km per hour and 90 km per hour, their length are 1.10kmand 0.9km. The time taken by the slower train to cross the fast train in second is?

They can't be moving in opposite directions otherwise they would never cross each other. Even if they were moving in the same direction, the slower train can't catch up to the faster train.

Answer 3

The time taken by trains that are running in opposite directions will always same for both slower or fast train. as-
relative speed = 140 Km/h (90+50)
distance to cover = 2 Km (1.1 + 0.9)

so the time taken
=2km / 140 km per hr
= 1 / 70 hr
= 1 / 70 x 60x 60 sec
= 51 3/7sec

Answer 4

For this question, we ought to benefit parity between the time of both trains. in view that prepare A began early, It had a a million hour head commence. It had lined precisely 20 kms even as B began its adventure. So if we commence counting from 8 am, the gap lined by both trains now turns into ninety kms because prepare A has already lined 20 kms. in view that they're transferring in route of one yet another, their mixed speeds are 40 5 km/h. they'll then take ninety/40 5 = 2 hourse to collide, which will be at 10:00 AM.

Answer 5

The problem is erratic. The meaning of the phrase `their length are' is ambiguous. I think it may be the distance of the trains from a reference point.
When the train are moving in opposite direction and when the reference point is not given, two things are possible 1) Trains may cross each other 2)They may not cross each other.
Consider both the trains start their journey from the same point that too having the end points of the trains at the reference point. Then they never cross each other. If they start with their faces at reference point then the trains cross each other. This is just a single example that I have given. You can yourself think off several such logical cases.

Answer 6

The total distance to be covered is 1.10km + 0.90 km = 2 km
since both trains are in opp. direction so the speed of the slower train will be 50km/hr + 90km/hr = 140km/hr
Now time taken = distance/speed
so 2/140 hr = 1/70 hr
or,
1/70 x 3600 sec = 51.43 sec (approx)

Answer 7

The relative speed of train will be (50+90) Km/hr because both of them moving in the opposite direction
Total distance =1.1+0.9=2
relative speed is =140 Km/hr
Time to cross each other=Total distance/relative speed
= 2/140
=0.0142 hr
Time take in the second =0.0142*3600
=51.4 second

Time taken always same for both slower and fast train when the move in the opposite direction but it sloer train can't cross the fast train when both of them move in the same direction

Answer 8

their relative speed=140 kmph
slower train will have to cover 2 km @ 140 kmph
so the time taken=2/140hr=1/70 hr=53 secs approx.

Answer 9

For trains moving in opp direction

Relative speed = 90 + 50 = 140 kmh

relative distacnce = 1.10 + 0.9 = 2.00 km

Relative time = (rel.. dist) / (rel.. speed)

= 2/140 hrs

= 2/140 x 3600 sec

= ..............sec

Answer 10

you said the trains are going in opposite directions; therefore, they won't cross