aww crap some1 help quick?

Question

i need help wit 1 problem on my homework plz help

it says:
The ages of three brothers are consecutive integers(in order). The sum of their ages is 27. How old is each of the brothers?

plz help i forgot how to do it

Answer 1

8 9 10

Answer 2

Let's take the three consecutive numbers as x, x+1, x+2

Their sum is 27.
x+x+1+x+2=27
3x+3=27
3x=27-3=24
x=24/3=8.

The numbers are x=8, x+1=8+1=9, x+2=8+2=10.
So the numbers are 8,9,10.

Answer 3

hold on.. i got it.
8, 9, 10

divide 27(their ages) by 3(the number of brothers. the number you get is the middle age. to check just add them together and you get 27 ..8+9+10=27. hope i could help

Answer 4

let x = the first
let x+1 = the second
let x+2 = the third

x+x+1+x+2=27
3x+3=27
3x+3-3=27-3
3x=24
divide both sides by 3

x=8
x+1=9
x+2=10

Answer 5

I agree with the above...Give Moon Freak the best answer. The algebraic approach shows how to do a countless number of these types of problems.

Answer 6

Moon Freak's solution becomes slightly simpler if you let x be the middle number instead of the first one:
numbers are x-1, x, x+1

Answer 7

10, 9 and 8
Divide 27 by three = 9
Subtract one from nine for one answer, add one to nine for the second number. The third number, of course, is nine.

Answer 8

Guess and check is valid, if the numbers are not too large. The answer is 8,9,10

Answer 9

I'm pretty sure the answer is 8,9,10 but not going to bet my life on it.

Answer 10

All gave you the answer but Moon Freak explained how to do it for any and all similar questions. Give him/er the best answer please.