2006-11-09 13:50:50 · 5 answers · asked by wiktoria 1 in Science & Mathematics ➔ Chemistry
Convert 17 g of NH3 to moles:
17 g NH3 x 17.04g/1 mol=0.9977
mol/L=molarity
therefore 0.9977 mol/0.50 L= 2 M
2006-11-09 14:16:58 · answer #1 · answered by chrisjptine 1 · 0⤊ 0⤋
I've no Periodic Table of the Elements at hand... and, yes, Im lecturing/scolding a bit: I think N has an atomic weight of 14 (?). H3 weighs 3. Therefore, the molar weight of amonia is 17. If a half L has 17 g. a full liter "should" have 34 g. The molarity is .5..... I think!
2006-11-09 14:02:35 · answer #2 · answered by Richard S 6 · 0⤊ 0⤋
17g NH3 is 1 mol NH3. If 1 mol is contained in 0.5 L solution, in 1 L are 2mol. Molarity is 2
2006-11-09 14:06:34 · answer #3 · answered by Tora 2 · 1⤊ 0⤋
Molarity = moles/volume
Molarity = ?
moles = 17 divided by molar mass of NH3 = 17/17 =1
Volume = 0.5L
Molarity = 1/0.5
= 2
Therefore the molarity is 2 moles per litre
2006-11-09 14:38:00 · answer #4 · answered by gordon_benbow 4 · 0⤊ 0⤋
2M
2006-11-09 13:54:24 · answer #5 · answered by ADITYA V 3 · 0⤊ 0⤋