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2006-11-09 13:24:52 · 8 answers · asked by martha l 1 in Science & Mathematics Mathematics

8 answers

3(2x+3)+6=5(2x+3)
6x+9+6=10x+15
6x+15=10x+15
15=4x+15
30=4x
30/4=x
15/2=x or x=15/2

2006-11-09 13:28:48 · answer #1 · answered by kool5aban 2 · 0 0

The procedures above are all correct. However, just in case you didn't understand where 6x +9 +6 = 10x +15 came from...You have to distribute the 3 through the parentheses by multiplication.
3 times 2x + 3 times 3. This gets rid of the parentheses. Do the same for the other side of the equation.

2006-11-09 22:23:15 · answer #2 · answered by schlance2003 2 · 0 0

3(2x+3)+6=5(2x+3)
6x+9+6=10x+15
6x+15=10x+15
4x=0
x=0
so The answer is x=0 .
You can get it . I wish this could help you to find out the answer .

2006-11-10 01:50:34 · answer #3 · answered by Chong Sian C 3 · 0 0

3(2x +3) + 6 = 5 (2x + 3)

6 = 5 (2x +3) - 3 (2x+3) = (5-3)(2x+3) = 2 (2x +3)

6= 2 (2x+3) = 4x + 6
0=4x
x=0

15=15 CHECK

2006-11-09 21:30:09 · answer #4 · answered by Kyler 1 · 0 0

6x + 9 + 6 = 10x + 15

Subtract 6x from both sides (so the only x term is on the right) and subtract 15 from both sides (only constants on the left), then solve for x. You should get x = 0 as the solution.

2006-11-09 21:27:46 · answer #5 · answered by Hy 7 · 0 0

6x+9+6=10x+15
6x+15=10x+15
0=4x
x=0

2006-11-09 21:39:49 · answer #6 · answered by OK123 5 · 0 0

6x + 9 + 6 = 10x + 15
10x - 6x + 15 - 15 = 0
4x = 0

so x=0

helped?

2006-11-09 21:28:07 · answer #7 · answered by Migrant 2 · 0 0

do the same kind of thing that i gave you the other answer for.... same method, just different numbers....

2006-11-09 21:30:51 · answer #8 · answered by camm300 4 · 0 0

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