5r-2r-8=16
3r-8=16
adding 8
3r=24
dividing by 3
r=8
2006-11-09 12:39:25
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answer #1
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answered by raj 7
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Simplifying
5r + -1(2r + 8) = 16
Reorder the terms:
5r + -1(8 + 2r) = 16
5r + (8 * -1 + 2r * -1) = 16
5r + (-8 + -2r) = 16
Reorder the terms:
-8 + 5r + -2r = 16
Combine like terms: 5r + -2r = 3r
-8 + 3r = 16
Solving
-8 + 3r = 16
Solving for variable 'r'.
Move all terms containing r to the left, all other terms to the right.
Add '8' to each side of the equation.
-8 + 8 + 3r = 16 + 8
Combine like terms: -8 + 8 = 0
0 + 3r = 16 + 8
3r = 16 + 8
Combine like terms: 16 + 8 = 24
3r = 24
Divide each side by '3'.
r = 8
Simplifying
r = 8
2006-11-10 13:39:14
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answer #2
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answered by buzz kill 3
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to remedy 5r-(2r+8)=16. you should imagine your self that the minus register the front of the parenthesis is -a million. So now the equation might want to be 5r-a million(2r+8)=16. Distribute the -a million. which means -a million might want to multiply to 2r and eight. Now you get 5r-2r-8=16. upload or subtract the like words. 5r-2r-8=16 might want to develop into 3r-8=16. upload 8 to each and each and every area because you want to go away 3r on one area first. Now it may nicely be 3r=24. ultimately you'll divide by 3 to go away r or any variable on my own. The is r=8. desire this allows you.
2016-11-28 23:41:30
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answer #3
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answered by anuj 3
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5r - (2r + 8) = 16
5r - 2r - 8 = 16
3r - 8 = 16 (Add 8 to both sides)
3r = 24 (Divide both sides by 3)
r = 8
Check:
5(8) - (2(8) + 8) = 16
40 - (16 + 8) = 16
40 - 24 = 16
16 = 16
QED
2006-11-09 12:56:19
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answer #4
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answered by CSUFGrad2006 5
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5r-(2r+8)=16
distribute the -
the equation becomes
5r-2r-8=16
combine like terms (5r-2r= 3r)
to get rid of the -8, add 8 to both sides.
the equation becomes
3r= 24
r=8
yes you got the answer right :)
2006-11-09 12:39:09
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answer #5
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answered by Gwyn 3
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Well you need to distribute that negative sign through 2r+8.
5r - 2r - 8 = 16 ... then add like terms
3r -8 = 16 ... then isolate R.
3r = 24
r = 8
You were right! Hope that helped. :)
UMRmathmajor
2006-11-09 12:39:01
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answer #6
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answered by UMRmathmajor 3
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yea tahts right
2006-11-09 12:42:35
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answer #7
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answered by Doctor 2
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are you asking for the answers to your homework???
2006-11-09 12:38:31
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answer #8
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answered by Anonymous
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