A diving board of length L = 3.00 m is supported at a point a distance 1.00 m from the end, and a diver weighing 550 N stands at the free end View Figure . The diving board is of uniform cross section and weighs 300 N.
Find the force at the support point.
Find the force at the end that is held down.
2006-11-09 11:45:12 · 3 answers · asked by darkangelwattitude 1 in Science & Mathematics ➔ Physics
OK, I have found both these forces.
What should I do now?
2006-11-09 12:00:01 · answer #1 · answered by D.F 6 · 0⤊ 0⤋
View figure..but it's not here. Anyway, let me guess a little what this problem is about.
Let F1 be the force at the support point, and F2 the force at the end that is held down. Now take moments about F2:
300*3=F1*1
F1=900N upward direction.
Next, take moments about F1:
300*2=F2*1
F2=600N downward direction.
Note: please draw the diving board with all the forces there: F1,F2, and 300N. This way you can understand why F1 is in the upward direction, and F2 is in the downward direction.
2006-11-10 01:11:30 · answer #2 · answered by tul b 3 · 0⤊ 1⤋
May the force be with you always
2006-11-11 14:25:06 · answer #3 · answered by Anonymous · 0⤊ 1⤋