A ship that weighs 10,000 tons(mass 10 million kg) must displace what volume of fresh water to float?

Question

I also need help with other physics questions so if anyone is good at physics please have pity and send help! Also please send equations used with answers, so that I can learn to do it myself.

Answer 1

The definition of a kilogram (original) was the weight of one litre of pure water at its maximum density (which is just under four degrees centigrade). Ignoring the temperature variation (small) and the small effect of dissolved gases in fresh water, this means that a cubic metre of water weighs a tonne. (Metric tonne is 1,000 kilograms) Salt water as in the oceans is just a little more dense, which is why the question speaks of fresh water.

Answer 2

According to Archimede's principle, the same amount of water must be displaced to float a ship. So the water must displace 10 million kilogram and since fresh water has a density of 1 g/cm^3.
and density,D is defined as the ratio of mass,M to volume,V

D = M / V = 1 g/cm^3

then Volume

V = M / D = ( 10 x 10^6 kg * 10^3 g / kg) / 1 g/cm^3 = 10^10 cm^3

and 1 cm^3 = 0.000264 gallons

V = 2.64 x 10^6 gallons

Answer 3

The ship must displace an amount of water equal to it's own weight. (Archimedes principle). In this case therefore it has to displace 10*(10^6)Kg = 10*(10^6)Kg*(1liter/Kg)=10*(!0^6)liters=10*(!0^6) liters*(1 cubic meter/1000 liters)=10*(10^3 cubic meters) =10,000 cubic meters.
In the above equations, ^ stands for the exponentiation sign .i.e. 10^3 = 10 raised to 3 or 1000. Similarly 10^6 = 10 raised to 6 or 1 million.

Answer 4

the ship floats because it experiences Archimedes force
Fa = DVg (V here is the volume of water displaced ; D here is the density of water)
Fa = P so that the ship can float

DVg = mg => V = m/D = 10^7 / 10^3 = 10^5 L

Answer 5

water that weights 10000 tons
therefore....10000 cubic meters...

Answer 6

10,000(1.025)=tons of water it displaced