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A 72.0 kg box slides down a 29 degree ramp with an acceleration of 3.5 m/s/s. The acceleration of gravity is 9.81 m/s/s. Find the coefficient of kinetic friction between the box and the ramp. How would I solve this? I'm tilting the problem so that the only part that needs to be broken into components is the Fg.

2006-11-09 11:04:05 · 5 answers · asked by Audrey M 1 in Science & Mathematics Physics

5 answers

when u will draw ur inclined plane and mass on it there r different forces acting in it
first force will be directly perpendicular to the ground level i.e. Fg=mg
second force acting is mgcos(theta) which is perpendicular to hypotenuse of the inclined and makes up Fn=mgcos(theta)
then another component parallel to the hyp. of the inclined
which equals mgsin(theta) which goes down the ramp
and then u can
equal the force going down with the frictional force
mgsin(theta)-(mew)mgcos(theta)=ma
(as we know frictional force is (mew)Fn=(mew)mgcos(theta) )
solve by putting values
mew=0.146 ans

2006-11-09 11:33:22 · answer #1 · answered by Anonymous · 0 0

Unless the box has an engine the only acceleration is from gravity.
To find the coefficient of friction you'll need;initial speed,length of the ramp traveled and time elapsed.
There are two forces,one pulling orizontally and the other pulling down.
Solve with trigonometry for 29 degree and you'll have the distance covered in the elapsed time.
Compare this with the original time and the difference is due to friction.

2006-11-09 11:42:40 · answer #2 · answered by domedweller2 3 · 0 0

Draw a right triangle.
Alright, assuming the problem is on earth, the downward velocity (y) would have to be converted into newtons.

72 kg (mass) x 9.8 m/s (a) = Force in Newtons

Then you draw a mini right triangle with the vectors you are given under the object. Its hard to explain but you should've been taught it.

You then use trigonometry to finish the problem.

2006-11-09 11:07:41 · answer #3 · answered by gloves1931 2 · 0 0

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2016-09-01 10:00:07 · answer #4 · answered by ? 4 · 0 0

I'd be glad to help you. I teach physics. Messenger me on Yahoo! Messenger and we'll discuss it. My ID is
fortitudinousskeptic
- Kevin

2006-11-09 11:26:35 · answer #5 · answered by Anonymous · 0 0

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