English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

1. KCl solution and a AgNO(3) solution.


2. Na(2)SO(4) solution and a Ba(NO3) (2) solution.

2006-11-09 10:41:30 · 3 answers · asked by nst 1 in Science & Mathematics Chemistry

3 answers

KCl(aq) + AgNO3(aq) --> KNO3(aq) + AgCl(s)

Net ionic: Cl-(aq) + Ag+(aq) --> AgCl(s)

Na2SO4(aq) + Ba(NO3)2 --> 2NaNO3(aq) + BaSO4(s)

net ionic: SO4(-2)(aq) + Ba(+2)(aq) --> BaSO4(s)

2006-11-09 10:51:00 · answer #1 · answered by Dimos F 4 · 0 0

Q1 Step 1: write down the full equation KCl(aq) + Ag(NO3) (aq) --> KNO3 (aq) + AgCl(s)

Step 2: identify the ionic species: K+, Ag+, Cl- and NO3-

Step 3: write down only the ions which change state (from aq to s) in the ionic equation
Ag+(aq) + Cl- (aq) --> AgCl(s)


Q2 Using a similar approach
Full equation: Na2(SO4) (aq) + Ba(NO3)2 (aq) --> 2NaNO3 (aq) + BaSO4 (s)
Ions: Na+, Ba2+, (SO4)2- and NO3-
Ionic equation: Ba2+ (aq) + (SO4)2- (aq) --> BaSO4 (s)

2006-11-09 19:10:27 · answer #2 · answered by rxn 1 · 0 0

1. KCl + AgNO3 -> KNO3 + AgCl
ionic : Cl- + Ag+ -> AgCl

2. Na2SO4 + Ba(NO3)2 -> 2NaNO3 + BaSO4
ionic : [SO4]2- + [Ba]2+ -> BaSO4

2006-11-09 18:52:54 · answer #3 · answered by James Chan 4 · 0 0

fedest.com, questions and answers