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2006-11-09 08:24:21 · 9 answers · asked by downey1951 1 in Science & Mathematics Mathematics

9 answers

241

2006-11-09 08:26:34 · answer #1 · answered by Anonymous · 0 1

According to the Roman Numeral System, where C stands for 100, X stands for 10, L represents 50 and capital 'i' represents 1, this number is 241.

Why? The two C's mean 200. The X before the L means "10 less than 50" (so, that's 40). Plus, the 1 at the end.

Hope this helps!

2006-11-09 16:27:22 · answer #2 · answered by Tim GNO 3 · 0 1

In Roman numberal, C=100 X=10 L=50 and I=1.
Second, if the number at left side is smaller than the number at the right side, that means subtraction; if the number at left side is equal or larger than the number at right side, that means addition.

100(+) 100 (+) 50 (+) 1 (-) 10=> 200 (+) 40 (+) 1 => 241.

2006-11-09 16:34:07 · answer #3 · answered by Anonymous · 0 0

C is 100
L is 50
X is 10
I is 1

If a small number precedes a larger one, it means that much less then the bigger number.

If a small number follows a larger one, it means it is added to the larger number.

If a number is written twice, it means twice whatever that number is worth.

Examples.

XC is 10 less than 100 = 90

CCX is 10 more than 200 = 210

CCL means 250 (200+50)

CCXL is 10 less than 250 = 240

CCXLI means 250 -10 +1 = 241

2006-11-09 16:46:08 · answer #4 · answered by rosie recipe 7 · 0 0

C = 100
X = 10
L = 50
I = 1

Roman numerals can be tricky to read... when a smaller number is to the left of a larger, you subtract... so let's walk through it...

C = 100
C = 100
XL = 50-10 = 40
I = 1

so 241

2006-11-09 16:29:19 · answer #5 · answered by disposable_hero_too 6 · 1 0

212

2006-11-09 16:38:49 · answer #6 · answered by Anonymous · 0 0

CCXII = 212
CCXLI = 241

2006-11-09 16:28:34 · answer #7 · answered by Roberto 3 · 1 0

if it is ccxii then it means 212

2006-11-09 16:26:42 · answer #8 · answered by moonfreak♦ 5 · 1 0

212
Lower case is not allowed but has to be converted to upper case.

2006-11-09 16:27:28 · answer #9 · answered by Anonymous · 0 0

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