2006-11-09 07:37:07 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
there are 6 vertices and you form 4 triangles from the first 2, then 3, then 2, then 1 for a total of 14.
Now we form other triangles that overlap and it gets really complex...
I count 18 smaller triangles, for a total of 32 so far...
Now middle triangles...
36, for a running total of 68
2006-11-09 07:47:47 · answer #1 · answered by disposable_hero_too 6 · 0⤊ 0⤋
If you choose one of the corners of a hexagon it is already connected to its two neighbouring corners (they are linked by the outside edges of the hexagon)
That leaves three available corners to join up with on the opposite side of the hexagon.
When you draw lines to join up with those it will split the interior space of the hexagon into 4 triangles.
I'm not sure what will happen if you join EVERY corner to EVERY other corner and just keep going like that - but I dont think thats what you want
2006-11-11 03:34:42 · answer #2 · answered by Stanleymonkey 2 · 0⤊ 0⤋
I got 18 triangles and 6 quadrilaterals.
2006-11-09 15:47:51 · answer #3 · answered by suzieq_64093 4 · 0⤊ 0⤋
yes over 60
2006-11-09 15:52:39 · answer #4 · answered by SCARFACE 2 · 0⤊ 1⤋
n-2, if it's a 60-gons, then there is 58 triangles.
2006-11-09 15:41:41 · answer #5 · answered by kula o 2 · 0⤊ 1⤋
i STUDIED ALGERBRA IN 12TH GRADE, AND I WAS ASKED THAT QUESTION, THE ANSWER IS 82.
2006-11-09 15:41:12 · answer #6 · answered by Jenny C 1 · 0⤊ 0⤋
i dont care always hated maths!
2006-11-09 15:38:28 · answer #7 · answered by muffinplattsie 3 · 0⤊ 1⤋