Help with math!!! come on you smart people...help!?

Question

I need to find an equation for a rational function with the following asymptotes:
vertical asy: x=6, and x=-1
horizontal asy: y=-9

thanks for any help!!!

Answer 1

To have vertical asymptotes at x = 6 and x = -1, the denominator should have factors of (x - 6) and (x + 1), making it x^2 - 5x - 6. To have a horizontal asymptote of -9, the numerator should be of the same order as the denominator, but with a coefficient for the greatest exponent of x that is -9 times that of the denominator. The denominator is 2nd order with a coefficient of 1 for x^2, so the numerator can be -9x^2.

-9x^2 / (x^2 - 5x - 6)

Answer 2

i think these should work

-9x^2/[(x-6)(x+1)]

-9x^2/(x^2-5x-6)