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I haven't taken Algebra in over 18 years please help.

2006-11-09 07:22:21 · 3 answers · asked by Lucky1lady 1 in Science & Mathematics Mathematics

3 answers

-2x + h
In about 5 minutes you will be taken the limit of the expression as h ---> 0. Then, you will be told that then it will be the derivative.

After that you take 2 - x^2 do the derivative and get -2x.

2006-11-09 07:52:50 · answer #1 · answered by Dr. J. 6 · 0 0

Substitute (x + h) for x in (2-x^2) to get f(x + h)
[2 - (x + h)^2 - (2 - x^2)]/h
Expand the expression:
[2 - (x^2 + 2xh + h^2) - (2 - x^2)]/h
[2 - x^2 - 2xh - h^2 - 2 + x^2]/h
All sorts of terms drop out:
[- 2xh - h^2 ]/h =
Dividing by h (we only let h approach 0, not equal 0):
- 2x - h
Now you can make h so small that you can ignore it (otherwise known as "fudging" and making h = 0, since you no longer have to worry about division by 0)

2006-11-09 15:39:01 · answer #2 · answered by Helmut 7 · 1 0

i'm in mth 107 right now... i hated the difference quotient but here it is...:
m=(f(x+h)-(f(x)) / ((x+h)-x = (f(x+h)-(f(x)) / h
CRAZY!
example:
f(x)=2x^2-3x
should equal out to be
=4x+2h-3
hope it helps!

2006-11-09 15:28:52 · answer #3 · answered by ilovemegirl 1 · 0 0

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