How to solve this type fraction?

Question

I have this on a college entrance exam.

1/2
+ 1/3
- 2/3
______

I looked for a solution but couldnt find one

Thank You.

Answer 1

You need to find a common denominator. In this case, 6.

1/2 = 3/6, 1/3 = 2/6, and 2/3 = 4/6

So, the new question is...

3/6
+ 2/6
- 4/6
_____
1/6

Answer 2

Very easy. I am surprised this is on a college entrance exam. I am assuming what is being asked is to convert the fraction into a decimal like 0.625. Solving is easy like a division problem.

Take the first one - 1/2. Here 1 is the numerator and 2 is the denominator. Since the numerator is smaller than the denominator, this is called a proper fraction. To solve this, add a 0 on the right side of the numerator, which is the equivalent of multiplying it by 10. That makes it 10. Because of that your answer should have a decimal answer like 0.xxx. Note the dot in your answer (called a decimal) and a 0 value is before the decimal. Now let us find what will be the value after the decimal. You have now 10 on the numerator and 2 on the denominator. When 10 is divided by 2, we get a simple 5 with 0 remainder. Put the 5 right after the decimal. Since there is no remainder, that is it. Your answer is 0.5.

Let us take the +1/3. The + signs that the value is positive. A - sign says that the value is negative. Following the same steps like above, we note that this is a proper fraction too. So, let us add a 0 to the right after the numerator 1. Consequently your result is going to be 0 followed by a decimal and then some other numbers just like the previous problem. Ok, now you got 10 on the numerator and 3 on the denominator. When 10 is divided by 3, the answer is 3 with a remainder of 1. So, put the value 3 right after the decimal in your result. Since we got a remainder 1, we have to continue. Add a 0 to it. That makes it 10 again. Dividing that by 3 gives us 3 again with a remainder of 1. So put that 3 in the result which gives us 0.33. We can continue until there is no remainder. However this fraction will keep going giving us a real result of 0.33333333 or when reduced to two digits 0.33.

The third problem is for you to do. Hope that was clear. Good luck.

Answer 3

In order to add or subtract any fraction you have to have a common denominator. You do that by finding a number that both 2 and 3 have in common, that's called the least common multiple. Multiples are numbers that you multiply together to get a product. So... ask yourself 2x1=?, 2x2=? and so on. Then do the same for 3 until you get a product that is the same for 2 and 3. The least common multiple is 6. Then you need to change the denominators. Make sure that whatever you do to the bottom of the fraction, you do to the top part as well. (or else you will change the value of the fraction) So for 1/2 I will multiply both the top and bottom by 3 which will give me a new fraction of 3/6. I will multiply both parts of 1/3 by 2 and get 2/6 and do the same for 2/3 and get 4/6. Now that I have the same denominator, I can just keep the denominator, and add or subtract the numerators (that's the top part of the fraction) You should get an answer of 1/6.

Answer 4

a million. 3/7 - a million/5 = x/25 Multiply each term with 25 3/7 * 25 - a million /5 * 25 = x / 25 * 25 3*25 / 7 - a million*25 / 5 = x*25 / 25 seventy 5 / 7 - 25 / 5 = 25x / 25 seventy 5*5 / 7*5 - 25*7 / 5*7 = x 375 / 35 - one hundred seventy five / 35 = x 375 - one hundred seventy five / 35 = x two hundred / 35 = x two hundred/5 / 35/5 = x 40 / 7 = x x = 40 / 7 32. y + 9/y = -10 Multiply each term with y y*y + 9/y * y = -10 * y y^2 + 9 = -10y y^2 + 9 + 10y = -10y + 10y y^2 + 10y + 9 = 0 utilising Quadratic formula [ ax^2 + bx + c = 0 ] enable a = a million b = 10 c = 9 y1 = [ -b + sqrt ( b^2 - 4ac ) ] / 2a y1 = [ -10 + sqrt ( 10^2 - 4(a million)(9) ) ] / 2(a million) y1 = [ -10 + sqrt ( one hundred - 36 ) ] / 2 y1 = [ -10 + sqrt ( sixty 4 ) ] / 2 y1 = [ -10 + 8 ] / 2 y1 = -2 / 2 y1 = -a million y2 = [ -b - sqrt ( b^2 - 4ac ) ] / 2a y2 = [ -10 - sqrt ( 10^2 - 4(a million)(9) ) ] / 2(a million) y2 = [ -10 - sqrt ( sixty 4 ) ] / 2 y2 = [ -10 - 8 ] / 2 y2 = -18 / 2 y2 = - 9 therefor there is two values for y they're y1 = -a million y2 = -9 40 4. 7/z = 8/z - a million/11 Multiply each term with z 7 = 8 - z / 11 7 - 8 = - z / 11 -a million = - z / 11 a million = z / 11 a million*11 = z / 11 * 11 11 = z z = 11

Answer 5

You need to find the least common denominator. With 2 and 3, it is 6. So you need to change all the fractions to have a common denominator of 6 by mulitplying each fraction by the fractional equivalent to one--e.g., 3/3, 2/2, etc.

Good luck.

Answer 6

You can't do that fraction, and you want to go to college? Good luck, honey. You'll need it!! I did that kind of stuff in first grade.