the height of a box is 7 inches longer than the width. the length is 5 inches shorter than triple the width. let w be the width. give the sum of the height, width, and length.
a) 11w-5
b) 4w+2
c) 5w+2
d) 5w+12
i think its D, but not sure of it.
2006-11-09 06:23:41 · 5 answers · asked by gladdo19 1 in Science & Mathematics ➔ Mathematics
h=w+7
l=3w-5
h+w+l = w+7+w+3w-5 = 5w+2
So the correct answer is C.
2006-11-09 06:29:51 · answer #1 · answered by Pascal 7 · 0⤊ 0⤋
OK, start by writing the non-simplified expression: H = W + 7. L = 3W - 5. W + H + L = W + W + 7 + 3W - 5. That's the non-simplified expression. Now group the terms with W in them: W + W + 3W + 7 - 5. Now, add the common terms: 5W + 2. Sorry, it's C. You must have tried to add 5 inches instead of subtract them.
2006-11-09 06:29:32 · answer #2 · answered by Amy F 5 · 0⤊ 0⤋
Your first flow, it extremely is letting 2^x = y is a robust step in the direction of fixing the difficulty with lots ease. 2^(2x - a million) - 9*2^(x - 2) + a million = 0 [2^(2x) * 2^-a million] - 9[2^x * 2^-2] + a million = 0 Letting 2^x = y, enable's attempt to coach 2^(2x-a million) - 9*2^(x-2) + a million = 0 right into a recognizable quadratic equation. [y^2 * a million/2] - 9[y * a million/4] + a million = 0 (a million/2)y^2 - (9/4)y + a million = 0 2y^2 - 9y + 4 = 0 (2y - a million)(y - 4) = 0 y = a million/2 or 4 If y = 4: 2^x = 4 x = 2 If y = a million/2: 2^x = a million/2 x = -a million x could be -a million or 2. wish this enables!
2016-12-14 04:24:25 · answer #3 · answered by vogt 4 · 0⤊ 0⤋
no it's c....the sides are w, 3w-5, w+7. add em up
2006-11-09 06:28:36 · answer #4 · answered by Anonymous · 0⤊ 0⤋
C
2006-11-09 06:31:03 · answer #5 · answered by Christabelle 6 · 0⤊ 0⤋