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Consider a point in the ocean about 10.9 km deep. The pressure at that point is huge, about 1.12 X10^8 N/m2.

QUESTION:
What is the change in volume of 1.00 m3 of water carried from the surface to this point in the ocean in m^3?

2006-11-09 06:15:23 · 3 answers · asked by activegirl 1 in Science & Mathematics Physics

3 answers

First answer is not true. Water is slightly compressible. Per the reference: "Water at temperatures common in nature has a compressibility factor of around 0.0000034, meaning that a hydrostatic pressure of 6.89 kilopascals (1lb/ sq. in) would reduce unit volume by about 0.0000034 of the original volume. This compressibility of water is so slight we could never actually see it with our own unaided eyes. We might think water is not compressible. However, if that were the case then the oceans would be about 30 meters higher than they are now, and therefore cover an extra 5 million square kilometers of Earth!"
If you assume this compressibility is linear, like a spring, then the change in volume would be -0.0000034*1.12E8/6890.

2006-11-09 06:23:48 · answer #1 · answered by kirchwey 7 · 0 0

whilst water freezes, it expands. This improve helps gasses to fill the voids between the water molecules, transforming into buoyancy. If the ice is floating on desirable of the water, this implies somewhat of it is not interior the water. the burden of the quantity of ice is represented interior the water, yet no longer the quantity of the ice, by using fact a factor of it is not interior the water. (floating above the exterior). So the quantity might stay an identical. Now in case you have been to thoroughly submerge the ice interior the water, than the quantity could be somewhat much less whilst the ice melts.

2016-12-28 17:16:55 · answer #2 · answered by mayne 3 · 0 0

No volume change as water is not compressible.

2006-11-09 06:20:40 · answer #3 · answered by Anonymous · 0 0

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