how much tourque is needed to spin a 60lb disk at 3600rpm?

Question

i need to get it to speed in less than 30seconds.
where would i find this type of motor? or what kind of motor would be recomended?

the radius of the disk is 10.32
it is sollid and it is shaped like a cone

Answer 1

There isnt enough information here to calculate.

We need to figure out the inertia of the disk, the radius of gyration and things like that.. What are the dimensions of the 60 pound disk? Diameter will do if you tell me the material I can calculate the thickness. Oh yeah and while im at it, does the flywheel have spokes? or is it solid?

also i need to know which torque value you are looking for.. for instance it takes more torque to start a flywheel (breakaway torque) than it does to maintain its speed once it reaches the angular velocity you desire.

ok well the formula is given like this

t = (Wr^2 N) 308T
where t = time in seconds
Wr^2 = moment of inertia
N = Change in RPM
T= Torque in Ft Lbs

We ca rewrite the formula to solve for Torque this way
T= (Wr^2 N) / (308t)

i did a sample calculation based on a steel disk 60 pounds at 11.65" diameter, and 2" thick accelerating to 3600 RPM in 30 seconds and came up with the following.

T = (3.568x[3600]) / [308x30]
T= 12732/9240
T = 1.378 FtLbs of torque to accelrate to 3600 RPM in 30 seconds.

hope that helps