Doing a lab on Beer's Law.
If the stock solution contains .750g of glucose (molar mass 180.156g/mol) dissolved in 100mL deionized water. Thus the stock molarity would be .04163M yes?
Then dilutions are prepared with the stock solution with o-toluidine and deionized water to 100mL.
I'm given several values of volume of stock glucose, i.e. 10.00mL, 20.00mL, 25.00mL, etc.
How do I find the concentration of each solution?
2006-11-09 03:35:08 · 2 answers · asked by velmakelly777 1 in Science & Mathematics ➔ Chemistry
When you do dilutions you need to use M1V1=M2V2 to figure out the concentration of each solution. You know how much of the stock solution was put into each, and the volume of stock, and the total volume so use algebra and figure out the concentration of the diluted solution.
You haven't gotten to the phase where you use Beer's law. that comes after you test your dilutions and test an unknown.
2006-11-09 03:53:52 · answer #1 · answered by shiara_blade 6 · 0⤊ 0⤋
10.mL - .004163 M stock is dilluted 1:10
20 mL - 0.008326 M stock is dilluted 2:10
25 mL - 0.0104 M stock is dillued 2.5:10
2006-11-09 05:55:45 · answer #2 · answered by mashkas 3 · 0⤊ 0⤋