2006-11-09 03:14:03 · 0 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Providing that the H3C6H5O7 is citric acid, that balanced equation is:
H3C6H5O7 (s) + 3 NaOH (aq) --> Na3C6H5O7 (aq) + 3 H2O (l)
The net ionic equation is:
3 H+ (aq) + 3 (OH-) (aq) --> 3 H2O (l)
2006-11-11 20:20:41 · answer #1 · answered by Richard 7 · 74⤊ 1⤋
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If you follow the following 3 steps you will have little problem in writing ionic and net ionic equations: 1) write the balanced molaecular equation with states: (NH4)2CO3)aq) + BaCl2(aq) → BaCO3(s) + 2NH4Cl (aq) Now write a full ionic equation by showing all compounds that can dissociate, as ions. Anything that is (s), (g) or (l) dopes not dissociate. 2NH4-(aq) + CO3 2- (aq) + Ba2+(aq) + 2Cl-(aq) → BaCO3(s) + 2NH4- (aq) + 2Cl- (aq) The NET IONIC equation is written by examining the above ionic equation and deleting everything that appears the same on both sides of the → sign: Net ionic equation: CO3 2-(aq) + Ba2+(aq) → BaCO3(s)
2016-04-01 09:29:12 · answer #2 · answered by Sharon 4 · 0⤊ 1⤋
H3c6h5o7 Naoh
2016-11-10 01:44:53 · answer #3 · answered by mczell 4 · 0⤊ 0⤋
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2015-08-04 22:00:51 · answer #4 · answered by Anonymous · 0⤊ 0⤋