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For example, a fire hydrant shoots water at 200 liters a second, how to convert this to its velocity?

2006-11-09 02:58:56 · 3 answers · asked by Anonymous in Science & Mathematics Physics

3 answers

v(m/s) = Q(m3/s) / Nozzle Area(m2)

2006-11-09 03:35:48 · answer #1 · answered by Dr. J. 6 · 0 0

Hi,

Bernoulli's principle should help you out with this question.

V^2/2 + gh + P/d = Constant

Where:
V = Velocity of fluid
g= gravity
h = height
P = pressure
d = density.

In our case, gravity doesn't matter because we are talking about horizontal flow, so height is effectively zero. Also the density of water is defined as 1.

so now we have

V^2/2 + P = Constant = c

V^2 = 2(c - P)

V= Sqrt (2(c-P)).

Hope that helps,
Matt

2006-11-09 11:15:31 · answer #2 · answered by Matt 3 · 0 0

You need to know the size of the pipe/opening the water flows through.
then the volume per sec = velocity x area

2006-11-09 11:11:49 · answer #3 · answered by meg 7 · 0 0

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