Is the point (-3, 4) on the line y = (-1/2)x – (5/2)?

Answer 1

for this just substitute for x and y in eqn and see if LHS=RHS
LHS=4
RHS=(-1/2)(-3)-5/2
=3/2-5/2
=-2/2
=-1
not = RHS
so pt. not on line

Answer 2

This is quite easy:) What u have to do is substitute x=-3 (x=-3,y=4)and plug it into the equation and see what is the value of y. If the value of y=4, then it lies on the line. if u don't get4 as the ans, then the point does not lie on the line. In this case, this point does not lien on the line.y=(-1/2)(-3)-(5/2)=1

Answer 3

Plug in those points for that equation:
4=-1/2(-3)-5/2
4=3/2-5/2
4=-2/2
4≠-1
The correct point set would be (-3,-1)

To find the x-value for y=4, you do this:
4=-1/2x-5/2
-1/2x=8/2+5/2
-1/2x=13/2
(-2/1)-1/2x=13/2(-2/1)
x=-13
The correct point set for that one is (-13,4)

Check:
-1=-1/2(-3)-5/2
-1=3/2-5/2
-1=-2/2
-1=-1

4=-1/2(-13)-5/2
4=13/2-5/2
4=8/2
4=4

Answer 4

put value of x into the equation do you get y?

y= (-1/2)*-3 - 5/2
y= 3/2-5/2
y = 1 and not 4

So the answer is no

Answer 5

Hi Meg!

To check that, just make x = -3 and check if the result is y = 4. Just to tell you the result in advance, and answer to your queston is "yes".

Answer 6

yes

Answer 7

no it is not

Answer 8

no