x+8/x-3 + x-14/x-3=
2006-11-09 02:46:34 · 5 answers · asked by gloria j 1 in Science & Mathematics ➔ Mathematics
If you mean:
(x+8)/(x-3) + (x-14)/(x-3), then
(x+8+x-14)/(x-3)
(2x-6)/(x-3)
2(x-3)/(x-3)= 2
2006-11-09 03:03:32 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋
is that 8/x - 3 or 8/(x-3)? T clarify, are there 6 terms (separated by +'s or -'s) or 4 terms?
if 6, ans is 2x-6-6/x or (2x^2-6x-6)/x
if 4 ans is 2x-6/(x-3) or [2x(x-3)-6]/(x-3) or [2x^2-6x -6]/(x-3)
2006-11-09 11:09:29 · answer #2 · answered by rwbblb46 4 · 0⤊ 0⤋
(x+8+x-14)/(x-3)
2x-6/(x-3)
=2(x-3)/(x-3)
=2
2006-11-09 10:54:43 · answer #3 · answered by raj 7 · 1⤊ 0⤋
Can't simplfy something that doesn't equal anything.
2006-11-09 10:49:44 · answer #4 · answered by Anonymous · 0⤊ 1⤋
DONT PANIC!
2006-11-09 10:55:12 · answer #5 · answered by bros.parker 3 · 0⤊ 1⤋