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2006-11-09 02:12:58 · 4 answers · asked by Anonymous in Science & Mathematics Earth Sciences & Geology

4 answers

The entire San Andreas fault system is more than 800 miles long and extends to depths of at least 10 miles within the Earth.

2006-11-09 02:54:09 · answer #1 · answered by Geo06 5 · 2 1

Without giving you a Wikipedia answer, I will just say that the San Andreas is where the Pacific Plate is grinding against the North American plate in a transform fault. Most plate's either spread from each other (divergent) or one is subducted beneath the other. The San Andreas is a rare case where the plates rub against each other as one plate moves relatively north (Pacific Plate) and the other south (North American Plate). There is subduction of the Juan de Fuca Plate to the north in northern California which resulted in the creation of the Cascade range of volcanoes. It may be that the Juan de Fuca Plate and Nazca plates were once one plate that was subducted beneath North and South America. It is theorized that when a mid ocean ridge (a spreading center) was subducted, it resulted in an unusual situation where the plate being subducted (on the west side of the spreading center) was no longer moving enough relative to the North American plate to be subducted. It will probably resume being subducted in a few million years in my opinion, even though there has been some spreading in the south to open the gulf of california. Meanwhile that portion of the plate boundary that is not subducted or spreading apart will be called the San Andreas Fault and will be a major fault approximately 800 miles long. The plate boundarys are much longer.

2006-11-09 04:14:53 · answer #2 · answered by JimZ 7 · 0 0

"The entire San Andreas fault system is more than 800 miles long and extends to depths of at least 10 miles within the Earth. In detail, the fault is a complex zone of crushed and broken rock from a few hundred feet to a mile wide. Many smaller faults branch from and join the San Andreas fault zone."
"The San Andreas fault forms a continuous narrow break in the Earth's crust that extends from northern California southward to Cajon Pass near San Bernardino. Southeastward from Cajon Pass several branching faults, including the San Jacinto and Banning faults, share the movement of the crustal plates. In this stretch of the fault zone, the name "San Andreas" generally is applied to the northeastern most branch."

--from USGS, Schulz and Wallace, "The San Andreas Fault" at url below.

2006-11-09 02:39:50 · answer #3 · answered by luka d 5 · 1 0

The displacement of 0.016 meters according to 3 hundred and sixty 5 days is the completed displacement - the fee that the two cities are shifting in the direction of one yet another. So do exactly the maths - divide 559,000 meters by potential of 0.016.

2016-12-28 17:01:14 · answer #4 · answered by Anonymous · 0 0

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