I am looking for how to setup the problem to solve.
2006-11-09 01:46:43 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Take the mass of one mole of gold atoms (the molar mass in grams) and divide by Avogadro's number (the number of objects in a mole).
I haven't given the result because it sounds like you want to learn how to solve the problem and not just the answer.
2006-11-09 01:55:36 · answer #1 · answered by ihatedecaf 3 · 3⤊ 3⤋
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RE:
What is the mass in grams of a gold atom.?
I am looking for how to setup the problem to solve.
2015-02-03 04:33:47 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Molar Mass Of Gold
2016-10-05 11:14:35 · answer #3 · answered by dutel 4 · 0⤊ 0⤋
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mass Au(gold) per mol = 196.96 g/mol One mol of gold contains an 6.022 x 10^23 atoms mass of single atom of Au=196.96 g / 6.022 x 10^23 atoms Au atom=3.2706 x 10^-22 grams
2016-03-29 02:34:33 · answer #4 · answered by ? 4 · 0⤊ 0⤋
The molecular weight of gold is (197 by definition), then you would divide it by the number of atoms in a mole (6.2*10^23), which gives you a mass of 3.18*10^-22 g.
2006-11-09 01:54:49 · answer #5 · answered by Anonymous · 1⤊ 0⤋
If you are looking for the mass of a single atom of gold we need to know the atomic mass of this element:
M(Au) = 196.96 g/mol
1) One mol of gold contains an Avogadro number of atoms:
#atoms of Au = 6.022 x 10^23 atoms
2) If we divide the atomic mass over the Avogadro number:
mass of single atom of Au = 196.96 g / 6.022 x 10^23 atoms
mass of single atom of Au = 3.2706 x 10^-22 grames
That´s it!
Good luck!
2006-11-09 01:56:59 · answer #6 · answered by CHESSLARUS 7 · 9⤊ 0⤋