If 625g of Tylenol tablet contains 85% acetaminophen, how many moles of acetaminophen are present in the table

Question

Ahhh!

Answer 1

1) First of all we need to know the molecular mass of Acetaminophen (AC) or Paracetamol (molecular formula: C8H9NO2):

M(AC) = 151.17 g/mol [found in internet: wikipedia.org and checked in Sigma Aldrich catalogue]

2) The mass of AC in sample of Tylenol is:

m (AC) = (625 g)(0.85) = 531.25 g

3) Number of moles of AC are computed as follows:

n(AC) = m(AC) / M(AC) =531.25 g/151.17 g/mol = 3.51 moles

4) Answer is 3.51 moles of Acetaminophen


That´s it!

Good luck!

Answer 2

I would need to know the chemical structure of acetaminophen in order to figure out how many moles of it are present within the substance. :)

Answer 3

48.3 moles