Now this is easy, and fun.. I've just answered it... Can you?
Factorise Completely x^3 - 16x
Easy, easy easy!
2006-11-08 20:38:43 · 7 answers · asked by Miss LaStrange 5 in Science & Mathematics ➔ Mathematics
x³ - 16x
x(x² - 4²)
x(x - 4)(x + 4) =0
1. x = 0
2. (x-4) =0 :: then :: x=4
3. (x+4) =0 :: then :: x=(-4)
2006-11-08 23:27:50 · answer #1 · answered by safrodin 3 · 1⤊ 0⤋
Here we go:
x^3 - 16x = x*(x^2 - 16) = x*(x - 4)*(x + 4)
So, the answer is x*(x-4)*(x+4)
2006-11-09 05:20:36 · answer #2 · answered by Verbena 6 · 0⤊ 0⤋
First, factor a common x
= x(x² - 16)
Then, x² - 16 is a difference of 2 squares, so we can factor it
= x(x - 4)(x + 4)
Now, that is easy. Here is another challenge for you!
________________________
Factor the following completely:
x^4 + 4.
Contact me if you want an answer! Feel Free!
^_^
^_^
2006-11-09 07:04:46 · answer #3 · answered by kevin! 5 · 0⤊ 0⤋
x³ - 16x
= x(x² - 4²)
= x(x - 4)(x + 4)
2006-11-09 04:41:00 · answer #4 · answered by Wal C 6 · 0⤊ 0⤋
ill try!
x³ - 16x
= x(x² - 4²)
= x(x - 4)(x + 4)
sorry but hope this will help!
2006-11-09 04:56:41 · answer #5 · answered by Anonymous · 0⤊ 0⤋
x(x^2-4^2)
x(x-4)(x+4)
2006-11-09 05:06:03 · answer #6 · answered by wizkid!!! 3 · 0⤊ 0⤋
x³ - 16x
x(x² - 16)
x (x + 4)(x - 4)
- - - - - - - - - -s-
2006-11-09 06:25:49 · answer #7 · answered by SAMUEL D 7 · 0⤊ 0⤋