2006-11-08 18:42:16 · 6 answers · asked by err ryt.. 2 in Science & Mathematics ➔ Mathematics
4^(3x+1)=4^0
since the bases are the same the power can be compared
3x+1=0
adding -1
3x=-1
dividing by 3
x=-1/3
2006-11-08 19:02:16 · answer #1 · answered by raj 7 · 0⤊ 0⤋
4-3=1
2006-11-09 02:50:29 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Did you mean to solve it?
Your equation is ambiguous:
i)
4^(3x+1) = 1
3x+1=0
x = - 1/3
ii)
(4^3x)+1=1
4^3x=0
x=undefined
2006-11-09 02:52:36 · answer #3 · answered by dactylifera001 3 · 2⤊ 0⤋
Is it (4^3x) + 1 =1
or 4^(3x+1) = 1
???
2006-11-09 02:55:01 · answer #4 · answered by Anonymous · 0⤊ 0⤋
If your problem is:
((4^3)*x)+1=1
64x+1=1
64x=1-1
64x=0
x=0/64
x=0.
2006-11-09 03:03:14 · answer #5 · answered by Naveen 2 · 0⤊ 0⤋
x=0
Life's Lovely! Love & Live Life!
2006-11-09 03:04:50 · answer #6 · answered by Starreply 6 · 0⤊ 0⤋