how many distinct arrangments (permutations) of the word STATISTICS?

Answer 1

there are 10 letters
so arrangements possible=10!for distinct we must consider the repetitionos s 3 times,t 3 times,i two times
so dividing by 3!3!2!
the permutations are
10!/3!3!2!
=50400

Answer 2

Since you specified distinct arrangements, combinations is the proper term. If you had 10 distinct letters, you would have 10! combinations, but 2 letters are repeated 3 times and 1 letter is repeated twice, so
N =10!/3!/3!/2 = 50,400

10C5 = 252

Answer 3

The Letter Statistics has 10 Letters. So it can be arranged in 10! ways. But 'S' repeated 3 times, 'T' repeated 3 times and 'I' repeated 2 times. So The No. of Permutations will be 10!/(3!*3!*2!) = 50,400 permutations.

I hope ur fine with the answer. If so dont forget to rank me as best. Bye.......

Answer 4

there are two arrangements in maths: permutation and combination.

Permutation is arrangement in which order is not cared.

Combination is arrangement in which order is cared.

For STATISTICS, there are 10. but, since permutation is cared

order, there are 3'S' , 3'T' and 2'I'.

So, permutation for STATISTICS is 10!/ 3!3!2!

50400.

Answer 5

Its 10!/(3!*3!*2!)

Answer 6

(tot number of letters)!/(tot number of letter S)!/(tot num of letter T)! ....etc =10!/3!/3!/2!=50400