mn : what a great resource!
hmmm... is it a redox question?
2006-11-08 16:38:16
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answer #1
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answered by Myra G 5
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Answer: 2 (CaCl2) + 2(NaHCO3) + 2(H20) => 2(CaCO3) + 2(NaCl) + 2(H2) + Cl2 + O2
Steps:
CaCl2 + NaHCO3 + H2O => CaCO3 + NaCl + H2
There are 2 Cl's at the left but only 1 Cl at the right, therefore
CaCl2 + NaHCO3 + H2O => CaCO3 + 2(NaCl) + H2
There are 2 Na's at the right now but only 1 Na at the left, therefore
CaCl2 + 2(NaHCO3) + H2O => CaCO3 + 2(NaCl) + H2
There are 2 CO3's at the left now but only 1 CO3 at the left, therefore
CaCl2 + 2(NaHCO3) + H2O => 2(CaCO3) + 2(NaCl) + H2
There are 2 Ca's at the right but only 1 Ca at the left, therefore
2(CaCl2) + 2(NaHCO3) + H2O => 2(CaCO3) + 2(NaCl) + H2
There are 4 Cl's at the left but only 2 Cl's at the right,
but we cannot just add in another molecules to NaCl,
and that Cl cannot stand on its own, therefore
2(CaCl2) + 2(NaHCO3) + H2O => 2(CaCO3) + 2(NaCl) + H2 + Cl2*
There is an extra O at the left, but O cannot stand on its own, therefore
2 (CaCl2) + 2(NaHCO3) + 2(H20) => 2(CaCO3) + 2(NaCl) + 2(H2) + Cl2 + O2
The number of H2 is increased because of the increase of H20
2006-11-08 16:43:16
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answer #2
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answered by chingmenghang 3
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How Do You Balence out this equation?
CaCl2+2NaHCO3+H2O=CaCO3+2NaCl+H2+H2O
2006-11-08 16:53:44
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answer #3
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answered by yupchagee 7
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I'm pretty sure thats impossible.. because if you add more Cl's to the right side, you have to add more Na to the left, then you have to add more C to the right, then more Ca to the left, the more Cl to the right and then it repeats and it will never balance
2006-11-08 16:43:01
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answer #4
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answered by scurvybc 3
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WTF...you cant balance that, you must have made a mistake.
you sure its NaCl?
2006-11-08 16:43:26
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answer #5
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answered by asdrewq 1
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Try this website:
http://www.nitrogenorder.org/cgi-bin/balance.cgi
2006-11-08 16:33:17
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answer #6
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answered by Anonymous
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