Pressure Calculations~HELP!!! torr?

Question

If 1.47 x 10 raised to the -3 mol of Argon occupies a 75.0 mL container at 26 degrees Celcius, what is the pressure in torr??

If you could just tell me what to do on this that would be fantastic i really do not understand this!!

10 points to the first if not only one!

Answer 1

PV = NRT

N - Mols of argon

R = .0821
T = 26+273.15

V = 75/1000 to convert to L

Then you will find your P, pressure, in atmospheres.

convert that to torr

Answer 2

Argon at 26 C (=299.15 K) can be considered a perfect gas.
Therefore the perfect gas law, P V = n R T, can be used.

In consistent SI units:
[P] is in N/m^2 (Pascal)
[V] is in m^3
[n] is in mol
[T] is in Kelvins
[R] is 8.3144 J/(mol K)

Now the only other things you need to know are how many Torr per Pascal (approx. 7.5 E-3) and how many mL per m^3 (exactly 1 E-6)