What is the acceleration due to gravity at its location?

Question

A simple pendulum with a length 1.50 m makes 38.7 oscillations in 180 s. What is the acceleration due to gravity at its location? (It is not located on Earth!)

Answer 1

we have the formulae for simple pendulum to be
T= 2*pie*(l/g)^1/2

therefore g= (4*(pie^2)*l)/T^2

g= 1281.4058 ms^(-2)

since time period for simple pendulum only depends on its length and g therefore location is not important.