Graphing help please?

Question

Write an equation for the line parallel to the line -3x - 3y = 2
through (-3,-4)

Answer 1

First put the first equation into slope-intercept form or:

y = mx +b

m = slope, and b = y-intercept

-3x -3y = 2
+3x +3x

-3y = 3x + 2
/-3 /-3

y = -x + 2/3

So, your slope for the first equation is:

m = -1

To have a line parallel to the first line, the slopes must equal.



Use Point-Slope form.

y - y1 = m ( x - x1)

Since you are using the point (-3, -4)

y1 = -4

x1 = -3

So your new equation will be:

y - -4 = -1 ( x - -3)

(remember the slope must be the same)
(a minus a negative = a positive)
y + 4 = -1(x + 3)

y +4 = -x -3
-4 -4

y = -x -7

or you can put it back into standard form ( Ax + By = C)

x + y = -7

Answer 2

When it says a line parallel to another line,it means these two lines have the same slope.so we go to get the slope first from equation -3x-3y=2.
y = -1(x +2/3) => the slope is -1.
And the line passes through point (-3,-4). As you know, we can write an equation of a line with the slope and a point which it passes through.
So,the final answer is y - (-4) = -1 [ x - (-3) ] => y = -x -7.

Answer 3

I'll teach you step by step.

You need to get y by itself.
So add 3x to both sides to eliminate -3x.

-3y=2+3x

now you need to get rid of the -3, so divide both sides by -3.

you'd get y= -2/3 -x
or y= -x-2/3

the slope is -1/1, correct?

now plug in the (x,y)

-4= -1(-3)+b
-4= 3+b
b= -7

the solution will be

y= -x-7


I hope that helps more than just having the answer. :)

Answer 4

y = -x - 7