what number of moles of O2 is needed to produce 14.2 grams of P4O10(molar mass 284 grams) from P?
2006-11-08 12:03:42 · 3 answers · asked by Amanda R 2 in Science & Mathematics ➔ Chemistry
the answer is 0.250 mole
2006-11-08 12:26:12 · update #1
1) Write the balanced equation:
5O2 + 4P => P4O10
2) Determine how many moles of P4O10 there are in 14.2 g:
14.2/284 = 0.05 mole.
3) In the equation, determine what number you have to multiply the coefficients by so you get 0.05 mole of product. In this case, it's 0.05; so, multiply each coefficient by that number:
0.05*5O2 + 0.05*4P => 0.05P4O10
0.25O2 + 0.2P => 0.05P4O10
0.25 mole of O2 is the answer.
2006-11-08 13:05:25 · answer #1 · answered by pack_rat2 3 · 0⤊ 2⤋
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2016-05-16 02:07:59 · answer #2 · answered by Anonymous · 0⤊ 0⤋
.0625mol of O2
2006-11-08 12:25:03 · answer #3 · answered by bige1236 4 · 0⤊ 2⤋